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sizeof array pointer c知識摘要

(共計:20)
  • c - How to find the 'sizeof'(a pointer pointing to an array ...
    2009年1月29日 - int main() { int days[] = {1,2,3,4,5}; int *ptr = days; printf("%u\n", ... No, you can't. The compiler doesn't know what the pointer is pointing to.

  • getting size of array from pointer c++ - Stack Overflow
    2013年11月10日 - int largest(int *list, int highest_index) ... There's no way to do that. This is one good reason (among many) to use vectors instead of arrays. But if you ...

  • How can I get the size of an array from a pointer in C?
    2008年10月24日 - if (NULL == (p = calloc(sizeof(struct mystruct) * n,1))) { /* handle error ... No, there is no way to get this information without depending strongly on ...

  • c++ how to get the length of a pointer array? - Stack Overflow
    2013年4月2日 - char array[40] = "hello"; // size 40 int length = sizeof array / sizeof ... You can't, I'm afraid. You need to pass the length of the array to anyone who ...

  • Pointer to an array get size C++ - Stack Overflow
    2013年1月18日 - struct array { int *elements; //elements size_t size; //number of elements } ...

  • [Solved] How to calculate size of array from pointer variable ...
    2012年2月21日 - i have pointer of array(array which is in memory) .... Please see my article here:How to get size of array from its pointer[^]. Permalink.

  • sizeof - Wikipedia, the free encyclopedia
    When sizeof is applied to the name of a static array (not allocated through malloc), the result is the size in bytes of the whole array. This is one of the few exceptions to the rule that the name of an array is converted to a pointer to the first element

  • c - How to find the 'sizeof'(a pointer pointing to an array)? - Stack Overflow
    No, you can't. The compiler doesn't know what the pointer is pointing to. There are tricks, like ending ...

  • size of a sizeof(pointer) - C / C++
    size of a sizeof( pointer). C / C++ Forums on Bytes. 395,300 Members | 3,680 Online Join Now login + Ask ...

  • C:Why "sizeof(array_name)" gives array size but "sizeof(array_pointer)" gives pointer size?
    Consider the following Code snippet where for the sizeof operator I have used both array names and t... ...

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